If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12
<u>Solution:</u>
Given that , In a certain function, y varies directly with x
And x = 8 when y = 6,
We have to find what will be the value of x when y = 9
Now, from the given information,

where c is the proportionality constant

Hence, x value is 12 when y value is 9
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.
2. Where C(n, r)=

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.
4. Or we could do this with the formula C(3, 2)=

5. C(8, 6)=

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
Step-by-step explanation:
g of load= 30 kg ( kilogram)
load at top of building=20 kg( kilogram)
building height=13 m(meter)
<h2>or"= total work done=?</h2>
<h3> or"=. power developed by him= ? </h3>
now ,
30*20*13÷20
again ,30*20*13
________
20
answer,= 390
5x+2=2y+20+24
5x+2=2y+44
-2 -2
5x=2y+42
That's what I got...