Answer:
B. 61%
Step-by-step explanation:
When we have the standard deviation of a sample, we use the t-distribution.
The width of an interval is related to the margin of error, which is given by the following equation:
M = T*s
In which T is related to the confidence level(and the sample size) and s is the standard deviation of the sample. Higher confidence levels have higher values of T.
A higher margin of error means that the interval is wider. To have a higher margin of error, we desire a higher value of T, which is achieved with a higher confidence level.
So the correct answer is:
B. 61%
For this case we must find the product of the following expression:
![\sqrt [3] {5} * \sqrt {2}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5%7D%20%2A%20%5Csqrt%20%7B2%7D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
We rewrite the expression using the lowest common index of 6, then:
We rewrite the terms in an equivalent way:
We rewrite the expression using the property mentioned:
![\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%7D%20%2A%20%5Csqrt%20%5B6%5D%20%7B2%20%5E%203%7D%20%3D)
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So:
![\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%20%2A%202%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B6%5D%20%7B25%20%2A%208%7D%20%3D%5C%5C%5Csqrt%5B6%5D%7B200%7D)
ANswer:
Option b
Y=3.6x is direct variation. The constant is 3.6
8y=2x is the same as y=0.25x. It is direct variation, and the constant is 0.25
1. Assuming "dinners made" is on the y-axis, DV is y=2x. The constant is 2
2. This is not direct variation, and therefore does not have a constant of variation
Since 19 is a prime number it is not divisible by 2. So its only divisible numbers are 1 and 19 itself. So 19 multiplied by 1 equals 1
<span>Binomial Problem with n = 50 and P(op) = 0.0.7
P(31<=50) = 1 - P(0<=x<=30) = 1 - binomcdf(50,0.7,30) = 1-0.0848 = 0.9152
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