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fenix001 [56]
3 years ago
12

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
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1. La asistencia a un juego de béisbol profesional fue de 4500 personas y el dinero
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Resolviendo un sistema de ecuaciones veremos que se vendieron 900 boletos de $15 y 3600 boletos de $10.

<h3> ¿Cuántos boletos de cada tipo se vendieron?</h3>

Primero definamos las variables:

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Sabemos que se vendieron 4500 boletos, entonces:

x + y = 4500

Y se recaudo un total de $49,500, entonces:

x*$10 + y*$15 = $49,500

Entonces tenemos un sistema de ecuaciones:

Para resolver esto, primero debemos aislar una de las variables en la primer ecuación, voy a aislar x:

x = 4500 - y

Ahora reemplazamos esto en la otra ecuación:

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Ahora debemos resolver estoy para y.

$45,000 - y*$10 + y*$15 = $49,500

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y = ( $4,500)/$5 = 900

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x = 4500 - 900 = 3600

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Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

#SPJ1

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