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fenix001 [56]
3 years ago
12

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
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Answer:

Original number = 38

Step-by-step explanation:

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<em />

<em>I hope this information can help you.</em>

7 0
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