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fenix001 [56]
3 years ago
12

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
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Maru [420]

Answer:

15 pound in a bag

Step-by-step explanation:

one can= 8 oz

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Question asked how many pound is in one bag of dog food:

We know that 16 oz = 1 pound

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7 0
3 years ago
I don't understand this question
padilas [110]

Answer:

105 rooms

Step-by-step explanation:

quarter=1/4

total rooms=140

rooms cleaned=1/4×140=35

140-35=105

therefore total rooms remaining are 105 rooms

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1 year ago
Complete the solution of the equation. Find the value of y when x equals 8. 4x+9y=-14
Shtirlitz [24]

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3 years ago
(fractions) 8/9 + 3/18
SVEN [57.7K]

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13/18

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5 0
2 years ago
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Fiesta28 [93]

Answer:

2.79

Step-by-step explanation:

Given

With reference angle 21°

hypotenuse (h) = 3

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3 0
3 years ago
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