Using the balanced chemical equation below, calculate how many moles of ammonia would be produced when 9.1 moles of hydrogen gas
1 answer:
6.07 moles
Explanation:
Given parameters:
Number of moles of reacting hydrogen gas = 9.1 moles
Unknown:
Number of moles of ammonia produced = ?
Solution:
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
We should work from the known to the unknown specie. We known the number of moles of hydrogen gas reacting. We simply relate this to that of the ammonia.
From the reaction:
3 mole of hydrogen gas produced 2 mole of ammonia
9.1 moles of the hydrogen gas will produce:
= 6.07 moles
Learn more:
Number of moles brainly.com/question/1841136
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A) 1 cal
B) 80 cal
C) 540 cal
Explanation:
A)
The amount of heat energy needed to raise the temperature of a certain mass of a substance is given by
where
m is the mass of the substance
C is the specific heat capacity
is the change in temperature
In this problem:
m = 1 g is the mass of water
is the specific heat capacity of water
is the change in temperature
So, the heat needed is
B)
For a solid substance at its melting point, the amount of heat needed to melt completely the substance is given by
where
m is the mass of the substance
is the specific latent heat of fusion of the substance
In this problem:
- The ice is already at melting point, 0 °C
- Mass of the ice:
- Specific latent heat of fusion of ice:
So, the heat needed is
C)
For a liquid substance at its boiling point, the amount of heat needed to boil completely the substance is given by
where
m is the mass of the substance
is the specific latent heat of vaporization of the substance
In this problem:
- The water is already at boiling point, 100 °C
- Mass of the water:
- Specific latent heat of vaporization of water:
So, the heat needed is
Answer:
a. What impulse act on the ball during its collision with the floor?
b. If the ball is in contact with the floor for 0.04 s, what is the average force of the ball on he floor?
The answers to the question are
a. The impulse acting on the ball during its collision with the floor is
7.076 kg·m/s
b. The average force of the ball on the floor with contact of 0.04 s is
176.9 N
Explanation:
Mass of the ball = 0.61 kg
Initial velocity = -7 m/s
Final velocity = 4.6 m/s
Impulse = Δp = FΔt = mΔv
Where Δt =change in time
m = mass of Average force of he the ball
Δv = velocity change
Therefore impulse = m×(Final velocity - initial velocity)
= 0.61 × (4.6-(-7)) = 0.61×11.6
= 7.076 kg·m/s
b. Average force of the ball on the floor is given by
×Δt = mΔv = 7.076 kg·m/s
where Δt = change in time = 4.6 m/s
Therefore =mΔv /Δt = 7.076/0.04 = 176.9 kg·m/s²
= 176.9 N