False,<span>The opposite is true: the GCF of an odd number and an even number is always odd.
All the factors of an odd number are odd; or to put it another way: If a number has an even factor, the number itself must be even.
Thus the only common factors between odd and even numbers must be odd.
</span>
Answer:
1676
Step-by-step explanation:
The store started with 32500 items and finished the day with 30824 items.
Intial value = 32500
Final value = 30824
Difference = Initial value - Final value = 32500 - 30824 = 1676
The store sold 1676 items in the day
The scuba diver must descend 3 feet in the fifth minute to meet the goal.
Why?
To find how many feet does the scuba diver need to descend to reach the goal of 35 feet in 5 minutes, we need to calculate how many feet he did descend on the first 4 minutes.
So, calculating we have:
Hence, we can see that at the 4 minute, he has only descended 32ft. It means that he need to descend 3 feet more in the fifth minute.
Have a nice day!
Answer:
Here we have the domain:
D = 0 < x < 1
And we want to find the range in that domain for:
1) y = f(x) = x
First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)
f(0) = 0 is the minimum in the range.
f(1) = 1 is the maximum in the range.
The range is:
0 < y < 1.
2) y = f(x) = 1/x.
In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.
f(0) = 1/0 ---> ∞
f(1) = 1/1
Then the range is:
1 < x.
Notice that we do not have an upper bound.
3) y = f(x) = x^2
This function is strictly increasing, then:
f(0) = 0^2 = 0
f(1) = 1^2 = 1
the range is:
0 < y < 1
4) y = f(x) = x^3
This function is strictly increasing in the interval, then:
f(0) = 0^3 = 0
f(1) = 1^3 = 1
the range is:
0 < y < 1.
5) y = f(x) = √x
This function is well defined in the positive reals, and is strictly increasing in our domain, then:
f(0) = √0 = 0
f(1) = √1 =1
The range is:
0 < y < 1
Answer:9898
Step-by-step explanation:
bc 9+8=0-9
