The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
<h3>How to determine the total areas?</h3>
<u>The figure 1</u>
In this figure, we have
Length = x + 1
Width = 4
The area is calculated as:
Area = Length * Width
So, we have
Area = 4(x + 1)
<u>The figure 2</u>
In this figure, we have
Length = d + 4
Width = 7
The area is calculated as:
Area = Length * Width
So, we have
Area = 7(d + 4)
<u>The figure 3</u>
In this figure, we have
Length = y + 3
Width = y
The area is calculated as:
Area = Length * Width
So, we have
Area = y(y + 3)
Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
Read more about areas at:
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Answer:
In technical terms, the slope of the line is the change in y over the change in x. But I just like to think of it as rise over run. To find the slope of the line, pick two points on the line.
Answer:
118°
Step-by-step explanation:
When two parallel lines are cut by a tranversal, then the exterior angles are supplimentary and the corresponding angles are congruent.
Therefore the angle above (15x - 17)° is also (5x + 17)° and the angle below (5x + 17)° is also (15x - 17)°.
Angles on a straight line adds up to 180°. So to know the measure of the larger angle we must both equations and equal it to 180° to find x in order to know the larger angle.
(5x + 17) + (15x - 17) = 180
5x + 15x + 17 - 17 = 180
20x = 180
20x/20 = 180/20
x = 9°
Nkw let's substitute x = 9 into the equations
5x + 17 =
5(9) + 17 =
= 62°
15x - 17 =
15(9) - 17 =
= 118°
Both equations should add up to be 180°.
Therefore the measure of the largest angle is 118°.
Im guessing you can make a ratio out of this, 20/2.5=x/1, 20=2.5x, x=8, so there was a degree change of 8 in one hour
