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3 years ago

Define adaptation as a change that improves the change of survival for a species in a specific environment

Biology

1 answer:

KiRa [710]3 years ago

4 0

The action or process of adapting or being adapted.

"the adaptation of teaching strategy to meet students' needs"

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assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

Where is the best place to find information about the hazards that are associated with a compound

Marizza181 [45]

Material Safety Data Sheet (MSDS) is the best place to find information about the hazards that are associated with a compound. It is a document that gives the information on the potential hazards such as health, fire, reactivity and environmental and how to work safely with the chemical products.

-Rosie

3 0

3 years ago

Any factor that changes the shape of an enzyme can affect the enzyme's activity. Which of the following two factors affect an en

kupik [55]

Considering the choices;

A. blood glucose level and pH

B. amount of light and temperature

C. amount of light and pressure

D. temperature and pH

Answer;

D. temperature and pH

The two factors affect an enzyme's operation the most is the temperature and pH.

Explanation;

Enzymes work best at optimum pH and temperature.

At low temperature for example the enzymes are inactivated while at high temperatures enzymes are denatured.

At optimal temperature and pH; the chemical reaction rate is optimal.

4 0

3 years ago

Read 2 more answers

Dual innervation refers to an organ receiving A) both sensory and motor nerves.B) both sympathetic and parasympathetic innervati

Talja [164]

Answer:

The correct option is B.

Explanation:

Dual innervation is a biochemical process by which an organ receives two different types of stimulation simultaneously. The principal function of dual innervation is to maintain the homeostatic balance of the body system. Dual innervation is brought about by two different systems, the sympathetic and the parasympathetic nerve systems. Although the actions of these two nerve systems are opposites to one another, they work together to bring balance to the body system. Without dual innervation the homeostatic system of the body can not be maintained.

8 0

3 years ago

Which of the following is NOT a possible cause of conduction deafness?Select one:a. otitis mediab. middle ear infectionc. cochle

Agata [3.3K]

Answer:

b. middle ear infection

Explanation:

6 0

3 years ago