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3 years ago

What is the answer to 6/3 +10/4

Mathematics

2 answers:

rodikova [14]3 years ago

7 0

Answer:

6/3 + 10/4 = 4.5

Explanation:

6/3 = 2

10/4 = 2.5

2 + 2.5 = 4.5

Hope that helped!! :)

Tcecarenko [31]3 years ago

4 0

Answer:

4.5

Step-by-step explanation:

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Thepotemich [5.8K]

Answer:

i Dont know

Step-by-step explanation:

6 0

3 years ago

Simplify: 4x3+5y3+2x3+7y

zimovet [89]

6x^3 + 5y^3 + 7y

So the third option.

3 0

2 years ago

A bag of chips costs $3.79, including tax. Mr. Connor wants to purchase chips for his class and has a $15 budget. Write an inequ

Verizon [17]

Answer:

D. $3.79x $\leq$ $15

<em>Brainliest, please!</em>

Step-by-step explanation:

It costs $3.79 per bag of chips, and Mr. Connor can pay NO MORE THAN $15.

6 0

3 years ago

Read 2 more answers

Journalists try to use shorter or simpler words in their news stories whenever possible. The box below shows the number of lette

kap26 [50]

The mean, median number and the the outlier of the number of letters in the box is 5, 4.5 and no outlier respectively.

The complete question:

A box contains the numbers 9, 2, 2, 11, 1, 8, 8, 2, 6, 1, 7, 3.

<h3>How to find mean, median and outlier</h3>

Mean = Addition of all numbers ÷ number of digits

= (9 + 2 + 2 + 11 + 1 + 8 + 8 + 2 + 6 + 1 + 7 + 3) ÷ 12

= 60 ÷ 12

= 5

Median = The middle value arranged in ascending or descending order.

In ascending order; 1,1,2,2,2,3,6,7,8,8,9,11

There are two middle number; 6 and 3

Median = (6 + 3) / 2

= 9/2

= 4.5

There is no outlier

Learn more about mean and median:

brainly.com/question/14532771

6 0

2 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago