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Andrew [12]
3 years ago
5

2 < K on a number line

Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0
The circle is open on 2. shade right on the nimber line
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A right prism with rhombus bases is shown. The side length of each rhombus is 5 units. The height of the prism is 16 units. The
Papessa [141]
Volume of the prism:
V = B · h, where B stays for the area of the base and h stays for the height of the prism. And we know that d1 = 8, d2 = 6
B = ( d1 · d2 ) / 2 = ( 8 · 6 ) / 2 = 48 / 2 = 24
V = 24 · 16  = 384
Answer:
The volume of the prism is 384 cubic units.

5 0
3 years ago
Read 2 more answers
After dis if you get the answer right you get 50 points
svetoff [14.1K]

Answer:

5

Step-by-step explanation:

First you have 24-(5+9)/2

So do 5+9=14

24-14=10

10/2=5

answer is 5

7 0
2 years ago
Read 2 more answers
Help find the derivative.
Masteriza [31]

Answer:

Step-by-step explanation:

1.\\f(x)=e^x\\f'(x)=e^x\\2.\\y=x^8-12x^5-3x^2+7x+22\\\frac{dy}{dx}=8x^7-12*5 x^4-3*2x+7+0\\\frac{dy}{dx}=8x^7-60 x^4-6x+7\\3.\\f(x)=e^3\\f'(x)=0

5 0
2 years ago
The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 se
kakasveta [241]
Let:
x = cost of senior citizen ticket
y = cost of student ticket

4x + 5y = 102
7x + 5y = 126

4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4

7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4

note:
-35y/4 = -8.75y
714/4 = 178.5

-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14


x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8

x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea



6 0
3 years ago
In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each
Rudiy27

Answer:

N(t) = 972(1.015)^{t}

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

N(t) = N(0)(1+r)^{t}

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that N(0) = 972

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that r = 0.015

Then

N(t) = N(0)(1+r)^{t}

N(t) = 972(1+0.015)^{t}

N(t) = 972(1.015)^{t}

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

N(t) = 972(1.015)^{t}

N(12) = 972(1.015)^{12}

N(12) = 1162

The number of students enrolled in 2014 is 1162.

7 0
3 years ago
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