We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is

$P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}$

Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.

We can compute their probability and sum them: $\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788$

So, the answer is about 36.79%

3 0

3 years ago

Jaylan makes limeade using 3/4 cup water for every 1/5 cup of lime juice. Wanchen makes limeade using 2/3 cup of water for every

Alja [10]

Answer:

Wanchen's limeade has a weaker lime flavor.

Step-by-step explanation:

I don't know if this explanation makes sense but whatever.

7 0

3 years ago