Answer:
where is the full question?
Step-by-step explanation:
2x + 3 ≥ 7
2x ≥ 7 - 3
2x ≥ 4
x ≥ 4 / 2
x ≥ 2
2x + 9 > 11
2x > 11 - 9
2x > 2
x > 1
Those are your two inequalities, now we must find one that satisfies both. Combine them together you get:
1 < 2 ≤ x
That last inequality becomes your answer.
x ≥ 2 makes both statements true.
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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Answer:
0.6 miles per minute
Step-by-step explanation:
0.3 : 0.5
Multiply by 2
0.6 miles per minute
2 x 2 = 1 the interception of it
