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2 years ago

Draw a generic rectangle to multiply 37.42

Mathematics

1 answer:

aleksley [76]2 years ago

8 0

Draw a rectangle 37 cm by 42 cm and then count how many 1cm by 1cm squares are inside it.

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The space shuttle circled earth twenty times

AysviL [449]

Answer:

498020 miles al

Step-by-step explanation:

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2 years ago

Why is 2/3 greater than 3/5? Explain this to an 8 year old

Dmitrij [34]

$\text{Hey there!}$

$\bf{\frac{2}{3}=0.6\overline{6}7}\\\\ \bf{\frac{3}{5}=0.60}$

$\text{Reason: if you use a fraction pie chart and compare}\frac{2}{3} \text{to}\frac{3}{5}, \text{you'd see that}\frac{2}{3}$ $\text{has more shaded areas than as for}\frac{3}{5}\text{has the least amount}$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

8 0

3 years ago

Express 0.035 metre into km

azamat

Answer:

$0.000035km$

Step-by-step explanation:

$1km =1000m \\ x = 0.035m$

$use \: \: cross \: \: multipication$

$0.035 \times 1 = 1000x \\ 0.035 = 1000x \\ \frac{0.035}{1000} = \frac{1000x}{1000} \\ x = 0.000035km$

6 0

3 years ago

Read 2 more answers

4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail

Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

$h^{-1}(x)=\sqrt{\frac{x+1}{3}}$ ⇒ answer D

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = $f^{-1}(x)$

* Lets use these steps to solve the problems

∵ $f(x)=\sqrt{x-3}$

∵ f(x) = y

∴ $y=\sqrt{x-3}$

- Exchange x and y

∴ $x=\sqrt{y-3}$

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by $f^{-1}(x)$

∴ $f^{-1}(x)=x^{2}+3$

∵ g(x) = x² + 3

∴ $f^{-1}(x)=g(x)$

∴ The functions are inverses to each other

* Now lets find f(g(x))

- To find f(g(x)) substitute x in f(x) by g(x)

∵ $f(x)=\sqrt{x-3}$

∵ g(x) = x² + 3

∴ $f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x$

∴ f(g(x)) = x

∴ The functions are inverses; f(g(x)) = x

* Lets find the inverse of h(x)

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ $\frac{x + 1}{3}=y^{2}$

- Take √ for both sides

∴ ± $\sqrt{\frac{x+1}{3}}=y$

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ $\sqrt{\frac{x+1}{3}}=y$

- replace y by $h^{-1}(x)$

∴ $h^{-1}(x)=\sqrt{\frac{x+1}{3}}$

4 0

3 years ago

For (x)=3x+1 and g(x)=x^2 -6, find (f+g)(x)

julsineya [31]

Answer:

Step-by-step explanation:

$(f+g)(x)=f(x)+g(x)\\\\f(x)=3x+1;\ g(x)=x^2-6\\\\(f+g)(x)=(3x+1)+(x^2-6)=x^2+3x+1-6=x^2+3x-5$

4 0

3 years ago