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Tatiana [17]
3 years ago
10

WILL GIVE BRAINLIEST IF DO QUICKLY!!!!!: Let f(x) = 2/x and g(x) = x − 3. Write an expression for f(g(x))

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

I dont know sorry

Step-by-step explanation:

sorrrrrrry

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Twelve of the 20 students in Ms. Sarno’s homeroom are female. Each month, Ms. Sarno randomly selects a student to act as “teache
Ksivusya [100]

Answer:

C. A bag of 15 marbles , with 9 marbles representing female students, has a marble drawn 4 times with replacement

Step-by-step explanation:

i took the test and got it right ;)

3 0
3 years ago
Read 2 more answers
A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
3 years ago
Emily had some candy to give her five children.She first took two pieces for her self and then evenly divided the rest among her
kodGreya [7K]
She started with 17 pieces of candy
8 0
3 years ago
Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina com 1mx0,8m. Sabendo que ele recortou 2 triângulos, a
Gnom [1K]

Answer:

7190 cm²

Step-by-step explanation:

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina de 1 m x 0,8m.

Passo 1

Determine a área de todo o papelão

= Temos dimensões = 1mx0,8m

Área = Comprimento × Largura

= 0,8m²

Nós convertemos para cm²

1 m² = 10.000 cm²

0,8m² = x cm²

Multiplicação cruzada

0,8m² × 10.000 cm² / 1 m²

= 8000 cm²

Passo 2

Sabendo que recortou 2 triângulos, ambos com 20cm de base e 30cm de altura

Encontramos a área de um triângulo

= 1/2 × base × altura

= 1/2 × 20 × 30

= 300cm²

Ele cortou 2 triângulos Portanto, o são dos dois triângulos = 300cm² × 2

= 600cm²

etapa 3

Ele também cortou 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm.

A área de um trapézio =

1/2 (a + b) h

= 1/2 (10cm + 20cm) × 7cm

= 1/2 × 30 × 7

= 105 cm²

Ele cortou dois trapézios, portanto

A área dos dois trapézios do corte = 105cm² × 2

= 210 cm²

Passo 4

A área total do papelão que foi cortado = 600cm² + 210cm²

= 810 cm²

Etapa 5

Determine em cm² quanto de papelão sobrou.

Isso é calculado como:

Área total do papelão - Área total que foi cortada

= 8000 cm² - 810 cm²

= 7190 cm²

5 0
3 years ago
Quiana took out a loan to pay for a new car initially she owed the lender 15,234.68. she has repaid 247.43 of the loan each mont
mario62 [17]

Given Information:

Initial amount of loan = $15,234.68

Monthly payment = $247.43

Number of months = 5

Required Information:

Net change in loan = ?

Answer:

Net change in loan = $1,237.15 = $1,237(3/20)

Step-by-step explanation:

Quiana owed her lender an amount of 15,234.68 initially, she repaid the lender each month with an amount of $247.43 for 5 months, so the total amount that she repaid is

Total amount repaid = Monthly payment*Number of months

Total amount repaid = $247.43 × 5

Total amount repaid = $1,237.15

The remaining owed amount is given by

Balance = Initial amount of loan - Total amount repaid

Balance = $15,234.68 - $1237.15

Balance = $13,997.53

So the net change to the loan from Quiana's perspective over the past 5 months is,

Net change in loan = Initial amount of loan - Balance

Net change in loan = $15,234.68 - $13,997.53

Net change in loan = $1,237.15

or

Net change in loan = $1,237(3/20)

Therefore, the net change to the loan from Quiana's perspective over the past 5 months is $1,237.15

6 0
3 years ago
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