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FinnZ [79.3K]
3 years ago
15

Scenario: A tiger is running at a speed of 15 miles per hour. It's food , an antelope is 5 miles away running at a speed of 5 mi

les per hour.
1. ) Create the equation that describes how far the tiger runs after × hours

2. ) Create the equation that describes how far the antelope runs after × hours.

3. ) Where will each animal be after 0.25 of an hour?

4. ) When will the tiger catch it's food?
Mathematics
1 answer:
alekssr [168]3 years ago
6 0
Oh naw i cant do math
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Can you please help !? its due at 1:00 pm. (i will mark you brainlest) can you show work if you can?
11111nata11111 [884]

Answer:

10) 9*9*9*9 = 6561

11) 2*2*2 = 8

12) 3*3*3*3*3 = 243

13) 4*4*4 = 64

14) 6*6*6*6*6 = 7776

15) 5*5*5*5 = 625

16) 8.5*8.5*8.5 = 614.125

17) 1.3*1.3 = 1.69

18) 7*7*7*7 = 2401

Used a calculator

8 0
3 years ago
What is the area of the triangle?
balandron [24]

Answer:

24cm_2

Step-by-step explanation:

h=hbb

2

b= base

hb= height

and that is how u get... A= 24cm_2

6 0
3 years ago
20 POINTS What are the x-intercepts of the graph? A) x = -5 B) x = 1 and 5 C) x = 0 and 4 D) x = -1 and 5
Sedbober [7]

Answer:

<h2>B) x = 1 and 5</h2>

Step-by-step explanation:

x-intercept: the intersection point of the graph with the x axis.

Therefore, the x-intercepts are x = 1 and x = 5 (<em>look at the picture)</em>.

8 0
3 years ago
An architect measures a beam to be 96.55 centimeters long, with an accuracy of plus or minus 0.02 centimeter. Which equation can
olga2289 [7]

Answer:

|96.55−0.02|= x

|96.55+0.02|=x

Step-by-step explanation:

Given that:

Measured length of beam = 96.55 cm

Measurement accuracy = plus or minus (± 0.02cm)

Limits of actual length of the beam:

Let limit of actual length = x

Lower limit :

|measured length - accuracy| = x

|96.55 - 0.02| = x

96.53) x

Upper limit :

|measured length + accuracy| = x

|96.55 + 0.02| = x

96.57 = x

3 0
3 years ago
What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
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