Answer:
10) 9*9*9*9 = 6561
11) 2*2*2 = 8
12) 3*3*3*3*3 = 243
13) 4*4*4 = 64
14) 6*6*6*6*6 = 7776
15) 5*5*5*5 = 625
16) 8.5*8.5*8.5 = 614.125
17) 1.3*1.3 = 1.69
18) 7*7*7*7 = 2401
Used a calculator
Answer:
24cm_2
Step-by-step explanation:
h=hbb
2
b= base
hb= height
and that is how u get... A= 24cm_2
Answer:
<h2>B) x = 1 and 5</h2>
Step-by-step explanation:
x-intercept: the intersection point of the graph with the x axis.
Therefore, the x-intercepts are x = 1 and x = 5 (<em>look at the picture)</em>.
Answer:
|96.55−0.02|= x
|96.55+0.02|=x
Step-by-step explanation:
Given that:
Measured length of beam = 96.55 cm
Measurement accuracy = plus or minus (± 0.02cm)
Limits of actual length of the beam:
Let limit of actual length = x
Lower limit :
|measured length - accuracy| = x
|96.55 - 0.02| = x
96.53) x
Upper limit :
|measured length + accuracy| = x
|96.55 + 0.02| = x
96.57 = x
The percentage of the semicircle shaded section is approximately 23,606 %.
The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

(1)
Where:
- Area of the half cross, in square centimeters.
- Area of the semicircle, in square centimeters.
- Percentage of the shaded section of the semicircle.
And the percentage of the shaded section is:
![r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100](https://tex.z-dn.net/?f=r%20%3D%20%5Cleft%5B1-%5Cfrac%7B4%20%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%2B4%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%7D%7B0.5%5Ccdot%20%5Cpi%5Ccdot%20%2816%5C%2Ccm%5E%7B2%7D%2B4%5C%2Ccm%5E%7B2%7D%29%7D%20%5Cright%5D%5Ctimes%20100)

The percentage of the semicircle shaded section is approximately 23,606 %.
We kindly invite to check this question on percentages: brainly.com/question/15469506