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4 years ago

Can i get someone to answer this for me please?

Mathematics

2 answers:

denpristay [2]4 years ago

6 0

Answer:

B, D and also E

Step-by-step explanation:

Nimfa-mama [501]4 years ago

4 0

Answer:

A, E

Step-by-step explanation:

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Ok so last time i posted this there was a lot of confusion so your supposed to come up with a 4th grade math problem and then yo

ollegr [7]

Answer:

(8x7)\2+x=5

Step-by-step explanation:

8x7=56 \2=28 + x = 36.5

3 0

3 years ago

Evaluate the following equation for p:<br> -3p + 6 + 7p = 22

strojnjashka [21]

Answer:

Step-by-step explanation:

-3p+6+7p=22

-3p+7p=16

4p=16

p=4

5 0

3 years ago

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Jolene scored 21 goals over the past 18 lacrosse games. What was her average number of goals scored per game expressed as a deci

butalik [34]

Since Jolene scored 21 goals in 18 games, you divide the # of goals by the # of games(21÷18)

The answer is about 1.17 goals per game

6 0

3 years ago

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Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the re

alukav5142 [94]

Answer:

Step-by-step explanation:

$\text{Given that:}$

$y = 1+ sec(x) \ \ y =3$

$\text{we draw the graph and the curves intersect at:}$

$x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}$

$\text{Applying washer method;}$

$f(x) _{outer} - g(x) _{inner} --- (1)$

$V= \int ^b_a A(x) \ dx --- (2)$

$\text{outer radius = 3 - 1 = 2}$

$\text{inner radius =}$ $( 1 + sec(x) ) - 1 = sec (x)$

$A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)$

$\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx$

$V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx$

$V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx$

$V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx$

$V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}$

$V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )$

$\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}$

8 0

3 years ago

What's the common denominator of this equation?<br> 3 - b = 6-7

GuDViN [60]

Answer:

b = 4

Step-by-step explanation:

3 - b = 6 - 7

3 - b = -1

-b = -1 -3

-b = -4

b = 4

8 0

4 years ago

Read 2 more answers