<span>Sometimes true.
This deals with the definition of range, mean, and mode.
Range = difference between the smallest and largest number
Mean = average. Just add up all the numbers together and divide by the number of numbers in the list.
Mode = The number that occurs the most frequently.
Now for an example where two lists of numbers that have the same range and mean, but don't have the same mode
list_1 = {1, 2, 3, 3, 4, 5, 6, 7, 8, 9, 10}
range = 9
mean = 5.27
mode = 3
list_2 = {1, 2, 3, 4, 4, 4, 6, 7, 8, 9, 10}
range = 9
mean = 5.27
mode = 4
So the above 2 lists show a case where the range and mean match exactly, but they don't have the same mode.
Now for two different lists where their mode does match.
list_1 = {1, 2, 3, 3, 4, 5, 6, 7, 8, 9, 10}
Range = 9
Mean = 5.27
Mode = 3
list_2 = {1, 2, 3, 3, 3, 4, 5, 8, 9, 10, 10}
Range = 9
Mean = 5.27
Mode = 3
So as you can see, a 2 sets of data may have the same same and same mean and will only sometimes have the same mode.</span>
F = ks
<span>12 = k(15) </span>
<span>12/15 = k </span>
<span>integrating from 0 to 15 </span>
<span>12/15 sds </span>
<span>12/15 x S squared / 2 from 0 to 15 </span>
Parallel lines are lines that will never intersect, even if they [continue on forever] (I admit, I'm not entirely sure on that last part, since there might be something different.)
Lines that are not parallel will cross. We say that they will intersect, and we call the point an intersection.
You can think of angles as [a fragment of intersecting lines].
Sorry I couldn't be of much help, but I think there are quite a few possible answers to this haha
We have 2 types of tickets, A tickets and B tickets. The total number of tickets sold was 500, so an equation for this NUMBER of tickets is A + B = 500. The MONEY equation is something different. A tickets cost 10, so they are represented by 10A; B tickets cost 60, so they are represented by 60B. The total dollar sales for A and B are 6000. Our money equation for the sales is 10A + 60B = 6000. Solve the first equation for A: A = 500 - B. Sub that value for A into the second equation to solve for B: 10(500-B) + 60B = 6000. Distribute through the parenthesis to get 5000 - 10B + 60B = 6000. Combine like terms to get 50B = 1000. B = 20. There were 20 type B tickets sold. A = 500 - B, so A = 500 - 20 and A = 480. There were 480 type A tickets sold.
