Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]
The intersection of sets R and D is give by the following set:
R ∩ D = {3, 9, 15}.
<h3>What is the missing information?</h3>
This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.
<h3>What is the set that is the intersection of two sets?</h3>
The set that is the intersection of two sets is composed by the elements that belong to both sets.
For this problem, the sets are given as follows:
- R = {1,3,5,7,9,11,13,15,17}.
- D={3,6,9,12,15,18,21,24,27}
Hence the intersection is given by:
R ∩ D = {3, 9, 15}.
As the elements 3, 9 and 15 are the only ones that belong to both sets.
More can be learned about intersection of sets at brainly.com/question/11439924
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Hello from MrBillDoesMath!
Answer:
4( x + 1.5)^2 + 0
Discussion:
4x^2 + 12x + 9 = => factor "4" from first 2 terms
4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2
4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =
4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25
4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9
4 ( x+ 1.5)^2 + 0
Thank you,
MrB
Answer:
a) The arithmetic sequence with common difference 2 that has 8 as the first term.
b) The arithmetic sequence of common difference -5 and first term 15.
Step-by-step explanation:
Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:
8, and (8+2) = 10 Therefore the second term is 10.
Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:
15, and (15 - 5) = 10. Therefore again a 10 as second term.
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Answer:
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