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ziro4ka [17]
3 years ago
8

"A software package developed to handle information requirements for a specific type of business is called a horizontal applicat

ion"a. true.b. false.
Computers and Technology
2 answers:
boyakko [2]3 years ago
4 0

Answer:

false.

Explanation:

false.

A horizontal application is defined as any programme that covers a wide number of customers with various sets of skills and expertise. Since application like horizontal types can cover different sectors and can be useful in a number of industries and moreover these application are not area specific or market specific application.

goldfiish [28.3K]3 years ago
3 0

Answer:

<h3>False </h3>

Explanation:

Vertical application software it the software which if build as per the specific requirements for achieving specific processes and functions which are unique to a user or business. These softwares are customised as per the needs of an organisation or enterprise. these applications are useful for organisations operating in marketing, sales, inventory etc but cannot be used by other businesses. They are built to target specific users. ERP(Enterprise Resource Planning ) and CRM (Customer Relationship Management ) are examples of vertical applications.

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4 0
3 years ago
Write a program to define three variables to hold three test scores. The program should ask the user to enter three test scores
Elza [17]

Answer:  

It's always good to use if else with boolean expressions in such cases.

Explanation:

I have written a program  where I have used c# as programming language.

I used if else block with boolean expressions to enforce conditions to print the grades according to the average of test scores. I have used Logical And(&&) operator in boolean expressions so that all the conditions in if and if else  must be true

Here is the program:  

using System;

public class Test

{

   public static void Main()

   {

       int testScore1, testScore2, testScore3;

       Console.WriteLine("enter first testScore");

       testScore1 = Convert.ToInt32(Console.ReadLine());

       Console.WriteLine("enter second testScore");

       testScore2 = Convert.ToInt32(Console.ReadLine());

       Console.WriteLine("enter third testScore");

       testScore3 = Convert.ToInt32(Console.ReadLine());

       float avg = (testScore1 + testScore2 + testScore3) / 3;

       if(avg>=90)

       {

           Console.WriteLine("You got grade A");

       }

       else if(avg >=80 && avg <=89)

       {

           Console.WriteLine("You got grade B");

       }

       else if (avg >= 70 && avg <= 79)

       {

           Console.WriteLine("You got grade c");

       }

       else if (avg >= 60 && avg <= 69)

       {

           Console.WriteLine("You got grade D");

       }

       else if(avg< 60)

       {

           Console.WriteLine("You got grade E");

       }

       else

       {

           Console.WriteLine("Sorry, You failed");

       }

       Console.ReadLine();

   }    

}

Explanation of program:  

I created three variables named, testScore1, testScore2, testScore3 of datatype int. I prompted the user to enter three test score values. Each value is read using Console.ReadLine() . As the value entered is of type integer, I converted the  console read value into int using Convert method.  

In the next step, I calculated average using the formula.  

Now, Based on the average, I can calculate the grade according to the given grading scheme.

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3 years ago
If you were an attacker who wanted to gain access to a network, would you focus on breaching technical controls for applying soc
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Answer:

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Scareware. Scareware involves victims being bombarded with false alarms and fictitious threats. ...

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Phishing. ...

Spear phishing

Explanation:

thank me later

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3 years ago
/* ELEN 1301 Programming Assignment #5. Name : Your name. Student ID : Your student ID #. Due date : Due date Purpose of the pro
cestrela7 [59]

Answer:

Here is the C++ program:

#include<iostream> //to use input output functions

#include<iomanip> //to use setprecision

using namespace std; //to identify objects cin cout

int main() { //start of main function

     int n1, n2, n3, n4, n5, n6, n7, min, max;  // declare variables for 7 numbers, minimum value and maximum value

     double sum= 0; //declare variable to hold sum of 7 numbers

     double average;  //declare variable to hold average of 7 numbers

     cout<<"Enter first number: "; //prompts user to enter 1st number

     cin>>n1; //reads first number from user

     max = n1; //sets the first number to maximum

     min=n1; //sets the first number to minimum

     cout<<"Enter second number: "; //prompts user to enter 2nd number

     cin>>n2; //reads second number from user

     if(n2<min){ //if second number is less than min

          min=n2;      } //sets min to n2

     if(n2>max){ //if n2 is greater than max

          max = n2;      } //sets max to n2

     cout<<"Enter third number: ";  //prompts user to enter 3rd number

     cin>>n3; //reads third number from user

     if(n3<min){ //checks if n3 is greater than min

          min=n3;      } //sets n3 to min

     if(n3>max){ //checks if n3 is greater than max

          max = n3;      }      //sets max to n3

    cout<<"Enter fourth number: ";//prompts user to enter 4th number

     cin>>n4; //reads fourth number from user

     if(n4<min){  //if n4 is less than min

          min=n4;      }  //sets min to n4

     if(n4>max){  //if n4 is greater than max

          max = n4;      }  //sets max to n4

     cout<<"Enter fifth number: "; //prompts user to enter 5th number

     cin>>n5; //reads fifth number from user

     if(n5<min){  //if n5 is less than min

          min=n5;     }  //sets min to n5

     if(n5>max){  //if n5 is greater than max

          max = n5;      }  //sets max to n5

     cout<<"Enter sixth number: "; //prompts user to enter 6th number

     cin>>n6; //reads sixth number from user

     if(n6<min){ // if n6 is less than min

          min=n6;      }  //sets min to n6

     if(n6>max){  //if n6 is greater than max

          max = n6;      }  //sets max to n6

     cout<<"Enter seventh number: ";//prompts user to enter 7th number

     cin>>n7; //reads seventh number from user

     if(n7<min){  //if n7 is less than minimum number

          min=n7;      }  //assigns n7 to min

     if(n7>max){  //if n7 is greater than the maximum number

          max = n7;      }  //assigns n7 to max

     sum = n1+n2+n3+n4+n5+n6+n7;  //adds 7 numbers

     average = sum/7;  //computes average of 7 numbers

     cout<<"The average is: "<<fixed<<setprecision(3)<<average<<endl; //displays average value up to show 3 digits below decimal point using setprecision method of iomanip library

     cout<<"The maximum number is: "<<max<<endl; //displays maximum number of 7 numbers

     cout<<"The minimum number is: "<<min<<endl;  //displays miimum number of 7 numbers    

     return 0; }

Explanation:

The program is well explained in the comments attached to each statement of program. For example if

n1 = 3

n2 = 9

n3 = 7

n4 = 6

n5 = 2

n6 = 5

n7 = 4

When n1 is read using cin then this number is set to max and min as:

min = 9

max = 3

Now when n2 is read, the first if condition checks if n2 is less than min and second if condition checks if n2 is greater than max. As n2 = 9 so it is not less than min so this if condition is false and n2 is greater than max i.e. 3 so this condition is true. So 9 is assigned to max.

min = 9

max = 9

Now when n3 is read the values of min and max become:

min = 7

max = 9

Now when n4 is read the values of min and max become:

min = 6

max = 9

Now when n5 is read the values of min and max become:

min = 2

max = 9

Now when n6 is read the values of min and max become:

min = 2

max = 9

Now when n7 is read the values of min and max become:

min = 2

max = 9

Now the statement       sum = n1+n2+n3+n4+n5+n6+n7;

executes which becomes:

sum = 3 + 9 + 7 + 6 + 2 + 5 + 4

sum = 36.0

Next program control moves to statement:

average = sum/7;

this becomes

average = 36/7

5.142857

Since this is to be displayed up to 3 decimal places so average = 5.143

the complete output of the program is attached.

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