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Anarel [89]
3 years ago
5

You toss five fair coins. The probability that all five coins land heads is

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

1/32

Step-by-step explanation:

The question asks the probability that all five coins land heads

sertanlavr [38]3 years ago
4 0
<span><span>The answer is 10/32=5/16.
Here's how. 
At each step the choice is either heads or tails.
First toss, H or T.
Second toss, HH HT TH TT (example:first toss was H, second could be H or T and so on)
.
.
.
.
continue this way until you make a table with all possible values beginning with HHHHH and ending with TTTTT.
H H H H H
H H H H T
H H H T H
H H H T T
H H T H H
H H T H T
H H T T H
H H T T T
H T H H H
H T H H T
H T H T H
H T H T T
H T T H H
H T T H T
H T T T H
H T T T T

T H H H H
T H H H T
T H H T H
T H H T T
T H T H H
T H T H T
T H T T H
T H T T T
T T H H H
T T H H T
T T H T H
T T H T T
T T T H H
T T T H T
T T T T H
T T T T T
T T T T T
T T T T T
T T T T T 
You will have 32 possible outcomes .
5 heads -  
4 heads - 
3 heads - 
2 heads - 
1 head - 
0 heads - 

These are also numbers in the 6th row of Pascal's triangle of binomial coefficients.</span><span>
</span></span>
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Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

we have

AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

8 0
3 years ago
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