Answer:
7/12
Step-by-step explanation:
The probability is the number of events out of the number of outcomes. The total number of outcomes is the number of marbles which is 12. The number of events is the number of red or blue marbles which is 3 + 4 = 7. This is true since there are 3 blue listed and since 12 - 5 - 3 = 4 red.
The probability is a ratio or fraction and should be written as 7/ 12.
Answer:
Third choice from the top is the one you want
Step-by-step explanation:
This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out. For example:
and another example:
![\sqrt[12]{2^{12}}=2](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B2%5E%7B12%7D%7D%3D2)
Let's take this step by step. First we will rewrite both the numerator and the denominator in rational exponential equivalencies:
![\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B6%7D%20%7D%7B%5Csqrt%5B3%5D%7B2%7D%20%7D%3D%5Cfrac%7B6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%7D)
In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number. The LCM of 3 and 4 is 12. So we rewrite as

Now we will put it back into radical form so we can rationalize the denominator:
![\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B6%5E3%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E4%7D%20%7D)
In order to rationalize the denominator, we need the power on the 2 to be a 12. Right now it's a 4, so we are "missing" 8. The rule for multiplying like bases is that you add the exponents. Therefore,

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of
![\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D)
That looks like this:
![\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B6%5E3%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E4%7D%20%7D%2A%5Cfrac%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E8%7D%20%7D)
This simplifies down to
![\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B216%2A256%7D%20%7D%7B%5Csqrt%5B12%5D%7B2%5E%7B12%7D%7D%20%7D)
Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2! Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:
![\frac{\sqrt[12]{55296} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B12%5D%7B55296%7D%20%7D%7B2%7D)
Phew!!!
Answer:
3x+6x
Step-by-step explanation:
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Answer:
1
Step-by-step explanation:
x+2/2x=3/2
2x×3=2x+4
6x=2x+4
4x=4
x=4/4
x=1