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Ilya [14]
4 years ago
7

A ____ is a pair of equal ratios.

Mathematics
2 answers:
kobusy [5.1K]4 years ago
3 0
A Equivalent Ratio Is A Pair Of Equal Ratios.
ra1l [238]4 years ago
3 0
A proportion is a pair of equal ratios.

Hope this helps! Happy new years!! ^//^
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Law of Sines<br><br> A=?<br> B=?<br> C=?
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Which term is used to describe a number that makes a statement true?
frosja888 [35]
That is called the solution

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answer is solution
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hey certain cars value is said to depreciate by approximately 15% each year for the first eight years of the car originally cost
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What can you conclude about alternate interior angles?
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5 0
3 years ago
use the definition of countinuity to find the value of k so that the function is continuous for all real numbers
liubo4ka [24]

First of all, recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

So if <em>x</em> < 4, then <em>x</em> - 4 < 0, so |<em>x</em> - 4| = -(<em>x</em> - 4), and the first case in <em>h(x)</em> reduces to

\dfrac{|x-4|}{x-4}=\dfrac{-(x-4)}{x-4} = -1

Next, in order for <em>h(x)</em> to be continuous at <em>x</em> = 4, the limits from either side of <em>x</em> = 4 must be equal and have the same value as <em>h(x)</em> at <em>x</em> = 4. From the given definition of <em>h(x)</em>, we have

h(4) = 5k-4\cdot4 = 5k-16

Compute the one-sided limits:

• From the left:

\displaystyle \lim_{x\to4^-}h(x) = \lim_{x\to4}\frac{|x-4|}{x-4} = \lim_{x\to4}(-1) = -1

• From the right:

\displaystyle \lim_{x\to4^+}h(x) = \lim_{x\to4}(5k-4x) = 5k-16

If the limits are to be equal, then

-1 = 5<em>k</em> - 16

Solve for <em>k</em> :

-1 = 5<em>k</em> - 16

15 = 5<em>k</em>

<em>k</em> = 3

3 0
3 years ago
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