Quadratic function of Y=x2-2x-3

1 answer:

6 0

Ok! So, given a quadratic function, y = ax2 + bx + c, when "a" is positive, the parabola opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, y = x2, where "a" is 1.

Hope this helps.

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a line passes through (9, –9) and (10, –5).write an equation for the line in point-slope form. rewrite the equation in standard

Cerrena [4.2K]

The equation of the line in point-slope form is given by:
$y-yo = m (x-xo)
$
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:
$m = \frac{y2-y1}{x2-x1}$
Substituting values:
$m = \frac{-5-(-9)}{10-9}$
Rewriting:
$m = \frac{-5+9}{10-9}$
$m = \frac{4}{1}$
$m=4$
Now we choose an ordered pair:
$(xo, yo) = (10, -5)
$
Substituting values we have:
$y-(-5)=4(x-10)$
$y+5=4(x-10)$
We now rewrite the equation in its standard form:
$y = mx + b
$
Where,
b: cut with the y axis.
We have then:
$y = 4x - 40 - 5

y = 4x - 45$
Answer:
point-slope form:
$y+5=4(x-10)$
or
$y+9=4(x-9)$
standard form
$y = 4x- 45$