D. (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28
The question is incomplete:
James has dimes and quarters saved up in his change jar. He has a total of 162 coins totaling $31.20 what is the total amount james has in quarters?
a. $10.00
b. $6.20
c.$15.50
d.$25.00
Answer:
d.$25.00
Step-by-step explanation:
With the information provided, you can write the following equations given that dimes are equal to 0.10 and quarters to 0.25 to determine the number of dimes and quarters that James has:
x+y=162 (1)
0.10x+0.25y=31.20 (2), where:
x is the number of dimes
y is the number of quarters
First, you can solve for x in (1):
x=162-y (3)
Then, you have to replace (3) in (2) and solve for y:
0.10(162-y)+0.25y=31.20
16.2-0.10y+0.25y=31.20
0.15y=31.20-16.2
0.15y=15
y=15/0.15
y=100
Finally, you have to replace the value of y in (3) to find x:
x=162-100
x=62
Now, you know that James has 100 quarters and you can multiply this number for the value of a quarter to find the amount James has in quarters:
100*0.25=25
According to this, the answer is that James has $25 in quarters.
Answer:
80,000
Step-by-step explanation:
7 is the tean thousand
Add 1 because 5 is a big amount.
In the given expression 6X² + 13X +6, we can easily identify the values of a, b and c. These values are a=6, b=13 and c=6
For the value of "ac", we have:
ac=6*6
ac=36
For a sum of b are 4, we have
ac+b=36+13=49
Therefore, the answer for the last question "The two numbers that have a product of ac and a sum of b are 4 and 9".
