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Whitepunk [10]
3 years ago
8

Ms more wrote the following on the blackboard and asked her students to write it in fraction form:

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
660.011/1 would be equivalent to that expression
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What is the answer to <br> -x/4-2=x+3
lyudmila [28]

Answer:

-4

Step-by-step explanation:

6 0
3 years ago
Find the height of an equilateral triangle with sides of length 12
MAVERICK [17]

Answer:

Answer

sqrt(108)

6 sqrt(3)

10.3923

I don't know which answer you  want.

Step-by-step explanation:

  • Drop a perpendicular from the top angle to the base.
  • The base is cut into 2 equal parts.
  • Each part is 12/2 = 6
  • The perpendicular, as its name implies, meets the base at 90o.
  • You can use the Pythagorean Theorem to find the height.

h^2 = side^2 - (1/2 b)^2

h^2 = 12^2 - 6^2

h^2 = 144 - 36

h^2 = 108

Take the square root of both sides

h = sqrt(108)

h = sqrt(2*2 * 3 * 3 * 3)

h = 2 * 3 sqrt(3)

h = 6sqrt(3)

h = 6 * 1.7321

h = 10.3923

4 0
3 years ago
Read 2 more answers
Twelve diminished by six times a number
Vilka [71]

<span>Twelve diminished by six times a number</span>

<span> </span>

<span>12 - 6x </span>

3 0
3 years ago
1. Classify each statement as true or false for all real numbers a, b,<br> and c.
12345 [234]

naw

g4jtnbjtrnjbnrtibnrijnbngtrjnb jtkgnbrbgbn

6 0
3 years ago
I’m need this worked out step by step by tonight
Pie

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

  -7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

  -14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

  -9 ≤ 3x ≤ 19

Divide all parts by 3.

  -3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

  |f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

  |f(x)| > g(x)   ⇒   f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0
3 years ago
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