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Anika [276]
3 years ago
5

Question 1: Verify that parallelogram ABCD with vertices A(-5,-1), B(-9,6), C(-1,5), and D(3,-2) is a rhombus by showing that it

is a parallelogram with perpendicular diagonals.
Question 2 and 3 are down below.

Please show all work. Thank you.

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0
The first one can be proven by graphing the parallelogram and the diagonals.

The measure of angle 2 is 160 because it is a vertical angle to angle 1. The measure of angle 3 is 10 because the two other angles must each be 10 in order for the sum of all three angles to equal 180 for the triangles.

I have no idea for the third one however.

Hope this helps!

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2x^3-3x^2-11x+6 divide by x-3
Alexxx [7]

Answer: 2x^2+3x-2

Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

Your final step is to do \frac{-2x}{x} =-2. Write this -2 next to your other two parts

Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

2x^2+3x-2 times

4 0
3 years ago
Read 2 more answers
A radar gun used to determine the speed of passing cars must be within 7 mph of the actual speed of a selected car. If a highway
Marta_Voda [28]
Check that the radar pistol has an error of 7 mph.
 Then we have that:
 59 mph - 7 mph = 52 mph approximately.
 52mph <55mph
 Answer:
 He does not have irrefutable evidence that the car was speeding in a 55 mph zone
5 0
3 years ago
Hi. :) if you are a "Blink" what album should i get? ​
cricket20 [7]

Answer:

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Step-by-step explanation:

#teamtrees #WAP (Water And Plant)

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3 years ago
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Which statements are true for verifying the solution set of StartAbsoluteValue negative 2 x + 8 EndAbsoluteValue less-than 12 as
mariarad [96]

Answer:

I had to go back and double check, this was kind of confusing asking if  saying this statement is true or false is true or false.  So keep your eye on that.  as long as x is between (but not equal to) -2 and 10 then the inequality is true.  Fromt here you have to see if the option is SAYING it is true or not.

Step-by-step explanation:

I am assuming this is saying |-2x+8|<12 as -2 < x < 10

Substituting 10 for x into the original inequality will create a false statement.

True, since x has to be explicitly LESS THAN 10, not equal

Substituting 6 for x into the original inequality will create a false statement.

False, 6 is greater than -2 and less than 10

Substituting 20 for x into the original inequality will create a true statement.

False, greater than 10

Substituting –20 for x into the original inequality will create a false statement.

True.  Kinda confusing since it is asking if it is a false statement.  It is TRUE that it is a false statement.

Substituting –10 for x into the original inequality will create a true statement.

False, x needs to be between -2 and 10 (explicitly between and not equal to) to be true.  

Substituting 0 for x into the original inequality will create a true statement

True, it is between -2 and 10

8 0
3 years ago
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A store is having a sale on office
Natalka [10]

Answer:

c. $10.56

Step-by-step explanation:

$3.30 x 4 = $13.20 x 0.20 (20%) = $2.64

$13.20 - $2.64 = $10.56

4 0
3 years ago
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