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3 years ago

PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

LenaWriter [7]3 years ago

8 0

Answer:

A and H

Step-by-step explanation:

i don't know if H is really the answer

lora16 [44]3 years ago

4 0

Answer:

343.97

Step-by-step explanation:

The first one is 343.97. You times 324.5 with 6% also known as 0.006 which is 19.47.

Add 19.47 to 324.5 and you get 343.97

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14. Solve the Quadratic equation by the<br>method of completing square 3x2 - 8x - 3

Anna007 [38]

Answer:

x = -1/3 and x = 3

Step-by-step explanation:

I'm not sure, but I think you mean 3x^2 - 8x - 3 = 0

In that case:

1. Add 3 on both sides

3x^2 - 8x -3 + 3 = 3 -> 3x^2 - 8x = 3

2. Divide both sides by 3

x^2 - 8/3x = 1

3. Add ((8/3)/2)^2 to both sides

x^2 - 8/3x + ((8/3)/2)^2 = 1 + ((8/3)/2)^2

4. Simplify

x^2 - 8/3x + (4/3)^2 = 1 + (4/3)^2

x^2 - 8/3x + 16/9 = 1 + 16/9

5. Rewrite x^2 - 8/3x + 16/9 = 1 + 16/9 as a perfect square

and simplify 1 + 16/9

(x - 4/3)^2 = 25/9

6. Find the square root of both sides

$\sqrt{ (x -4/3)^2} = \sqrt{25/9}$

7. Simplify

(x - 4/3) = ±5/3

8. Rewrite the equation as two seperate equations

(x - 4/3) = ±5/3 ->

a. (x - 4/3) = 5/3

b. (x - 4/3) = -5/3

9. Solve for x by isolating the variable (add 4/3 to both sides)

a. x = 5/3 + 4/3

b. x = - 5/3 + 4/3

10. Simplify

a. x = 9/3 -> x = 3

b. x = -1/3

3 0

4 years ago

E probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the nu

pentagon [3]

The probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the null hypothesis is true is the definition of "P-Value."

<h3>What is null hypothesis?</h3>

A null hypothesis is a sort of statistical hypothesis which asserts that there is no statistical significance in a particular set of observations.

Using sample data, hypothesis testing is performed to determine the believability of a theory. It really is expressed as H0 and is also known to simply as "null."

Some key features regarding null hypothesis are-

A null hypothesis is a statistical conjecture that claims there is no variation between particular qualities of a population and data-generating process.
The alternate hypothesis asserts the existence of a distinction.
Hypothesis testing allows you to reject the null hypothesis with a particular level of confidence.
If the null hypothesis can be rejected, it lends support to the alternative hypothesis.
The notion of falsity in science is founded on null hypothesis testing.

To know more about null hypothesis, here

brainly.com/question/14016208

#SPJ4

8 0

2 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

Mkey [24]

Answer:

(a) Probability that 2 or fewer will withdraw is 0.2061.

(b) Probability that exactly 4 will withdraw is 0.2182.

(c) Probability that more than 3 will withdraw is 0.5886.

(d) The expected number of withdrawals is 4.

Step-by-step explanation:

We are given that a university found that 20% of its students withdraw without completing the introductory statistics course.

Assume that 20 students registered for the course.

The above situation can be represented through binomial distribution;

$P(X =r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,......$

where, n = number of trials (samples) taken = 20 students

r = number of success

p = probability of success which in our question is probability

that students withdraw without completing the introductory

statistics course, i.e; p = 20%

Let X = <u><em>Number of students withdraw without completing the introductory statistics course</em></u>

So, X ~ Binom(n = 20 , p = 0.20)

(a) Probability that 2 or fewer will withdraw is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}$

= $1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}$

= <u>0.2061</u>

(b) Probability that exactly 4 will withdraw is given by = P(X = 4)

P(X = 4) = $\binom{20}{4} \times 0.20^{4} \times (1-0.20)^{20-4}$

= $4845\times 0.20^{4} \times 0.80^{16}$

= <u>0.2182</u>

(c) Probability that more than 3 will withdraw is given by = P(X > 3)

P(X > 3) = 1 - P(X $\leq$ 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1-(\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}+\binom{20}{3} \times 0.20^{3} \times (1-0.20)^{20-3})$