32 × 2 = 68
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:
= 3.90625
Answer:
t = 51 - 25p
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
25p + 1t = 51
<u>Step 2: Solve for </u><em><u>t</u></em>
- [Subtraction Property of Equality] Subtract 25p on both sides: 1t = 51 - 25p
- Simplify: t = 51 - 25p
Answer:
x = - 26
Step-by-step explanation:
Let the number be x.
According to the question,
Cross multiplying 4 & 3 gives :-
And solving this eqn. gives :-
Verification :-
(putting the value of x = -26 )
Reducing by 7 gives .
Add 9, 6 times
And add 8, 7 times
Answer:
The term of A.P sequence
tₙ = 9 n - 26
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given sequence
- 17 , -8 , 1 .......
first term = -17
Second term = - 8
The difference of first two terms
d = - 8 -(-17) = -8+17 = <em>9</em>
The difference of next two terms
d = 1 - (-8) = 1+8 = 9
∴ The given sequence is in A.P ( Arthimetic progression)
<u><em>Step(ii):-</em></u>
The term of A.P sequence
Given a = - 17 and d = 9
<u><em>Final answer</em></u>:-
The term of A.P sequence
tₙ = 9 n - 26