E probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the nu
1 answer:
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Since M and N are independent events,
Step-by-step explanation:
Two events A and B are said to be independent when the probability of A happening does not depend on whether B has happened or not.
In other word, this condition can be rewrite as follows:
where
is the probability of A happening given that B has happened
is the probability of A happening
In this problem, we have:
- M and N are independent events: so M does not depend on whether N occurs or not
Therefore,
- Also, we know that
Therefore, it follows that
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1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.
There are in total
many ways of doing so.
where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r
2.
C(x, 2) is the total number of pairs out of x objects, that we can form.
so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.
The total number of games is:
n(x)=2*C(x, 2) =
Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.
Answer:
Consider a group of n objects. Assume we want to form groups of r, from these n objects.
There are in total
where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r
2.
C(x, 2) is the total number of pairs out of x objects, that we can form.
so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.
The total number of games is:
n(x)=2*C(x, 2) =
Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.
Answer: