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KiRa [710]
3 years ago
5

Draw a quick picture to show the number 24. Then draw a quick picture to show 24 after you have regrouped ten as ones. Explain h

ow both picture show the same number 24
Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Just draw 24 circles, or sticks, or stars, and then draw 10 little squares in a row twice, and 4 separate square. In the explanation say that there are 24 of whatever shape or thing you decided to draw and, for the regrouped say that 10+10+4=24 <span />
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Find the inverse of f(x) = 7x - 5.
dimaraw [331]

Answer:

f⁻1(x)=(x/7)+(5/7)

Step-by-step explanation:

To find the inverse, interchange the variables and solve for y.

5 0
3 years ago
The difference between (-7)2and -(7)2is
timofeeve [1]
The (-7) is negativing the 7 alone and -(7) is negativing the whole problem! I hope this helps
7 0
2 years ago
Travis has decided to budget his spending money. He can spend no more than $143.15 every month. He has also decided to spend 5.2
vivado [14]
143.15=5.2x is the answer to the problem
6 0
3 years ago
The product of three consecutive integers is -1716. what is the greatest of the three integers?
Monica [59]

Answer:

-11

Step-by-step explanation:

If we call x the least integer, then x + 1 is the next integer, and x + 2 is the greatest integer.

x (x + 1) (x + 2) = -1716

x (x² + 3x + 2) = -1716

x³ + 3x² + 2x = -1716

x³ + 3x² + 2x + 1716 = 0

That's not an easy equation to factor.  We could use rational root test, but that would take a long time.  However, we can narrow down the options logically.  The three integers are relatively close together, so if we approximated the product as x³:

x³ ≈ -1716

x ≈ -11.9

So let's see if x = -12 is a solution:

(-12)³ + 3(-12)² + 2(-12) + 1716 = 396

Nope.  Let's try x = -11:

(-11)³ + 3(-11)² + 2(-11) + 1716 = 726

Not that either.  Let's go the other direction, x = -13:

(-13)³ + 3(-13)² + 2(-13) + 1716 = 0

Aha!  x = -13.  So x + 1 = -12, and x + 2 = -11.

-11 × -12 × -13 = -1716

The greatest integer is -11.

6 0
3 years ago
Given is a finite set of spherical planets, all of the same radius and no two intersecting. On the surface of each planet consid
wariber [46]

Answer:

Step-by-step explanation:

To answer this question, First, we define a direction in space, which defines

the North Pole of each planet.

We also assume that the direction is not at 90° perpendicular to the axis of any two planet.

Assume we now define an order on the set of planet by saying that planet A ≥ B, when removing all the other planet from space, the north pole B, is visible from A.

If we refer to the direction of the planet in the diagram, we discover that,

1, A ≥ A

2, If A ≥ B and B≥ A,

Then A = B

3, If A ≥ B, and B ≥ C , then A ≥ C

4, Either A ≥ B or B ≥ A

It should also be noted that the array of order above has a unique maximal element  (M). This is the only  planet whose North Pole is not visible from another.

If we now consider a sphere of the same radius as the planets. Remove

from it all North Poles defined by directions that are perpendicular

to the axis of two of the planets. This is a set of area zero.

For every other point on this sphere, there exists a direction in

space that makes it the North Pole, and for that direction, there

exists a unique North Pole on one of the planets which is not visible

from the others. Hence the total area of invisible points is equal

to the area of this sphere, which in turn is the area of one of the  planets.

5 0
3 years ago
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