<h3>
Answer: choice B) counterclockwise rotation of 90 degrees around the origin</h3>
To go from figure Q to figure Q', we rotate one of two ways
* 270 degrees clockwise
* 90 degrees counterclockwise
Since "270 clockwise" isn't listed, this means "90 counterclockwise" is the only possibility.
<h2>Question :</h2>
<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>
<h2>Answer :</h2>
<em>y = -3/2x - 4 </em>
<h2>Explanation :</h2>
y = mx + c
*m = gradien
•>looking for gradients
y=2/3x+9
m1 = 2/3
m2 = -3/2
•>line equation (-6,5)
y - y1 = m(x - x1)
y - 5 = -3/2(x - (-6))
y - 5 = -3/2(x + 6)
y - 5 = -3/2 - 9
y = -3/2x - 9 + 5
y = -3/2x - 4
Answer:
The GCF is going to be 20
Step-by-step explanation:
This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here
The prime factorization of 20, 2 × 2 × 5= 20
The prime factorization of 80, 2 × 2 × 2 × 2 × 5 = 80
The common factors are 2, 2, and 5. We multiply those to get the GCF.
2 × 2 × 5 = 20
0.3*42 this gives you a 30% discount
3/10*42 this gives you a 30% discount
0.03*42 this gives you a 3% discount
3 *4.2 This is not a discount
Answer:
3,2,1,6,5,4
Step-by-step explanation:
Hope this helps!!!
