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3 years ago

Mike has a 9 foot long board. He needs to cut it into 12 equal parts. How many feet long should each section be?

1 answer:

3 0

Multiply 9 feet times 12 inches and you get 108 inches. Then take 108 inches and divide it by 12 sections, you get 9 inches.

Answer: Each section should be 9 inches long, or 0.75, or 3/4 feet long.

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podryga [215]

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Step-by-step explani belive you add it if it is improper then simplify hope it helps

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So I’m not great in math at all I spent 15 min crying because I don’t get it so anyone pls help

Yuri [45]

Answer:

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

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4 years ago

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Tom is the deli manager at a grocery store. He needs to schedule employees to staff the deli department at least 260 person-hour

Finger [1]

The expression that could best describe the statement would be " 40 n + 20 $\geq$ 260.

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4 years ago

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

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3 years ago