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ANTONII [103]
3 years ago
12

All of the following expressions are equivalent except _____.

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0
4.)-X+7 Hope this answer is useful to you
s2008m [1.1K]3 years ago
4 0

Answer:

1.) x-7

Step-by-step explanation:

hope it helps

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qaws [65]

its a virus dont  fall for it

Step-by-step explanation:

6 0
2 years ago
write an equation for a line that is parallel to line that passes through the points (5,5),(-1,3) and contains the point (-6,-8)
dimaraw [331]
Since the two lines are parallel then they have the same slope which = 1/3

since the line passes through (-6 , -8)

y+8 = (1/3)(x+6)

3y + 24 = x + 6

x - 3y = 18 is the equation
8 0
3 years ago
(3.8)(5,-9) what is this answer in standard form
marishachu [46]

Answer:

-15,2

Step-by-step explanation:

3.8 (5,-9)

Calculate the difference

3.8 (-4)

Multiply the numbers

3.8 x (-4)

-15,2

I hope this helps

3 0
3 years ago
8x+4y= -4 <br> what is the slope and y intercept of the line
jarptica [38.1K]

Answer:

y = -2x - 1 ; slope = -2, y-intercept = (0, -1)

Step-by-step explanation:

to get the slope and y intercept, you need to put the equation into slope-intercept form: y = mx + b

the term mx is the slope of the line, and b is the y-intercept

to do this, you need to solve for y, so get y by itself by subtracting 8x from the left side

8x + 4y = -4

-8x.          -8x

4y = -8x - 4

divide both sides by 4 to get y alone

4y/4 = y

-8x/4 = -2x

-4/4 = -1

y = -2x - 1 is the final equation

the slope of the line is -2 (also can be said as -2/1), and the line intercepts the y-axis at (0,-1)

8 0
3 years ago
Read 2 more answers
Solve: 10 2/3+2h≤4 1/3
PtichkaEL [24]

Answer:

\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}

Step-by-step explanation:

\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}

6 0
3 years ago
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