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gayaneshka [121]
3 years ago
14

Verify this cofunction identity by using the difference identity for cosine. Show your work! cos⁡(π/2-θ)=sinθ

Mathematics
1 answer:
taurus [48]3 years ago
8 0
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ

π/2 = 90°
cos(π/2) = cos90° = 0.        sin(π/2) = sin90° = 1

cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
                   = 0*cosθ + 1*sin<span>θ  = </span>sin<span>θ

Therefore  </span>cos(π/2 - θ) = sin<span>θ
 
QED   </span>
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den301095 [7]

Answer:

52.3m^2

Step-by-step explanation:

Use these formulas

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Now solve

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Answer:

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Step-by-step explanation:

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Write an equation ​(a) in​ slope-intercept form and ​(b) in standard form for the line passing through ​(22​,99​) and perpendicu
liberstina [14]
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5 0
3 years ago
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Answer:

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8 0
3 years ago
What is the area of a triangle that has a height of 10 feet and base length of 6 feet
disa [49]

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3 years ago
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