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2 years ago

Sour

Mathematics

1 answer:

notka56 [123]2 years ago

8 0

hello how are you? I am fine

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Pls help this is due today :)

Sedaia [141]

Answer:

Left 7 down 6 Then count two spaces left right up and down and draw a circle

Step-by-step explanation:

Your answer is going to be in the bottom left corner, you count 7 vertical lines to the left, then from there you count 6 horizontal lines down. Since the Radius is 2 the diameter is 4. Good luck, if this wasn't helpful enough you can get a graphing calculator for yourself.

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3 years ago

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Shelly biked 21 miles in 4 hours. What is shellys average speed in miles per hour? At the same rate how many hours will it take

tekilochka [14]

21 divide by 4 is 5.25. She travels 5.25 miles per hour. 42 divide by 5.25 is 8. It would take 8 hours for Shelly to bike 42 miles.

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3 years ago

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If the standard deviation of a data set were originally 12, and if each value in

Zanzabum

Answer: 21

Step-by-step explanation:

Take 12 and multiply it by 1.75 (12x1.75) and you’ll get 21

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3 years ago

The table below shows the number of students in th

Sphinxa [80]

The answer is c 8 in each row

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3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago