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Nadusha1986 [10]
3 years ago
7

7X^2/3--55X^1/3--8=0

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

x=\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}-\frac{157135}{686},\:x=-\frac{157135}{686}-\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}

Step-by-step explanation:

7x^{\frac{2}{3}}+55x^{\frac{1}{3}}+8=0

7\left(x^{\frac{1}{3}}\right)^2+55x^{\frac{1}{3}}+8=0

Rewrite as if x^{\frac{1}{3}}=u:

7u^2+55u+8=0

Use quadratic equation:

\frac{-55\pm \left(55^2-4\cdot \:7\cdot \:8\right)^{\frac{1}{2}}}{2\cdot \:7}

Solutions for this part:

u=\frac{-55+2801^{\frac{1}{2}}}{14},\:u=\frac{-55-2801^{\frac{1}{2}}}{14}

Substitute u=x^{\frac{1}{3}} back in:

x^{\frac{1}{3}}=\frac{-55+2801^{\frac{1}{2}}}{14}

\left(x^{\frac{1}{3}}\right)^3

=x^{\frac{1}{3}\cdot \:3}

=x

\left(\frac{-55+2801^{\frac{1}{2}}}{14}\right)^3

=\frac{\left(-55+2801^{\frac{1}{2}}\right)^3}{14^3}

=\left(-55\right)^3+3\left(-55\right)^2\cdot \:2801^{\frac{1}{2}}+3\left(-55\right)\left(2801^{\frac{1}{2}}\right)^2+\left(2801^{\frac{1}{2}}\right)^3

=11876\cdot \:2801^{\frac{1}{2}}-628540

=\frac{11876\cdot \:2801^{\frac{1}{2}}-628540}{14^3}

11876\cdot \:2801^{\frac{1}{2}}-628540\\

=4\left(2969\cdot \:2801^{\frac{1}{2}}-157135\right)

=\frac{4\left(2969\cdot \:2801^{\frac{1}{2}}-157135\right)}{14^3}

=\frac{2^2\left(2969\cdot \:2801^{\frac{1}{2}}-157135\right)}{2^3\cdot \:7^3}

=\frac{2969\cdot \:2801^{\frac{1}{2}}-157135}{7^3\cdot \:2^{3-2}}

=\frac{2969\cdot \:2801^{\frac{1}{2}}-157135}{7^3\cdot \:2}

=\frac{2969\cdot \:2801^{\frac{1}{2}}-157135}{7^3\cdot \:2}

=\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}-\frac{157135}{686}

x=\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}-\frac{157135}{686}

Now solve x^{\frac{1}{3}}=\frac{-55-2801^{\frac{1}{2}}}{14}:

x^{\frac{1}{3}}=\frac{-55-2801^{\frac{1}{2}}}{14}

\left(x^{\frac{1}{3}}\right)^3=\left(\frac{-55-2801^{\frac{1}{2}}}{14}\right)^3

\left(x^{\frac{1}{3}}\right)^3

=x^{\frac{1}{3}\cdot \:3}

=x

\left(\frac{-55-2801^{\frac{1}{2}}}{14}\right)^3

=\frac{\left(-55-2801^{\frac{1}{2}}\right)^3}{14^3}

\left(-55-2801^{\frac{1}{2}}\right)^3

=\left(-55\right)^3-3\left(-55\right)^2\cdot \:2801^{\frac{1}{2}}+3\left(-55\right)\left(2801^{\frac{1}{2}}\right)^2-\left(2801^{\frac{1}{2}}\right)^3

=-628540-11876\cdot \:2801^{\frac{1}{2}}

=\frac{\left(-628540-11876\cdot \:2801^{\frac{1}{2}}\right)}{14^3}

=\frac{-628540-11876\cdot \:2801^{\frac{1}{2}}}{14^3}

-628540-11876\cdot \:2801^{\frac{1}{2}}

=-4\left(157135+2969\cdot \:2801^{\frac{1}{2}}\right)

=-\frac{4\left(157135+2969\cdot \:2801^{\frac{1}{2}}\right)}{14^3}

=-\frac{2^2\left(157135+2969\cdot \:2801^{\frac{1}{2}}\right)}{2^3\cdot \:7^3}

=-\frac{157135+2969\cdot \:2801^{\frac{1}{2}}}{7^3\cdot \:2^{3-2}}

=-\frac{157135+2969\cdot \:2801^{\frac{1}{2}}}{7^3\cdot \:2}

=-\frac{157135+2969\cdot \:2801^{\frac{1}{2}}}{686}

=-\left(\frac{157135}{686}\right)-\left(\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}\right)

=-\frac{157135}{686}-\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}

x=-\frac{157135}{686}-\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}

Solutions:

x=\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}-\frac{157135}{686},\:x=-\frac{157135}{686}-\frac{2969\cdot \:2801^{\frac{1}{2}}}{686}

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