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sp2606 [1]
3 years ago
11

What are the domain and range of f(x) = |x – 3 | + 6? Domain: {x | x is all real numbers} Range: {y | y ≥ 6} Domain: {x | x ≥ 3}

Range: {y | y ≥ 6} Domain: {x | x is all real numbers} Range: {y | y ≥ – 6} Domain: {x | x ≥ 3} Range: {y | y ≥ – 6}

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
4 0

Answer:

Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.

Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.

sdas [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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3 years ago
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What 8 9/8 as a mixed number
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To make a fraction like this into a mixed number all you have to do is multiply the whole number times the denominator which would be 64; then add the numerator to your number which makes it 73 then add the denominator to the bottom. Thus, 73/8.
6 0
3 years ago
Please answer correctly !!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!
Mamont248 [21]
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7 0
2 years ago
Read 2 more answers
bernite is selling candy bars for a school fundraiser. the school paid $20 for a box of 15 king size candy bars and bernite sell
NikAS [45]
The school originally used $20 for the purchase of the candy.
Use the formula Y=2x to find how much money is made (y) from the number of candy bars (x)
Sub in the 15 bars for t
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Therefore the school made $10, because they earned an extra $10 in comparison to the amount they bought the candy bars for, which was $20.
Hope this helps!
6 0
3 years ago
Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
likoan [24]

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

5 0
3 years ago
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