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mart [117]
3 years ago
12

The list below shows the quantity of items purchased by customers at a particular checkout counter of a supermarket. 13, 6, 5, 9

, 12, 14, 18, 4, 13, 12, 4, 3, 11, 14 Create a histogram that correctly displays the data.

Mathematics
2 answers:
Arada [10]3 years ago
4 0

Answer:

A histogram is a bar-diagram which shows the frequency of certain data.

If we elaborate frequency table, it would be like

Number    Frequency

    3                   1

    4                   2

    5                   1

    6                   1

    9                   1

    11                   1

    12                  2

    13                  2

    14                  2

    18                  1

Where the total number is N = 14

Now, to graph this table as a histogram, we first need to label each axis. The horizontal axis will represent Numbers and the vertical axis will represent Frequency.

Then, the vertical axis will have marked number 1 and number 2. The horizontal axis will have mared numbers from 3 to 18, as the image attached shows.

After that, we will draw a bar, where each height will be the frequence. Refer to the image attached to see the histogram.

s2008m [1.1K]3 years ago
3 0

Answer:

The histogram can have four ranges.

Step-by-step explanation:

To make a histogram you need to separate the data in ranges and check how many values fall into each range. The number of values that fell in a range is going to be the height of the bar.

Arranging the values in increasing order:

3,4,4,5,6,9,11,12,12,13,13,14,14,18

The minimum value is 3 and the maximum is 18. If you make four ranges (you can choose the number of ranges): from 3 to below 7, from 7 to below 11, from 11 to below 15, from 15 to below 19.

The number of values that fall in each category is:

5 in the range from 3 to below 7 (3,4,4,5,6).

1 in the range from 7 to below 11 (9).

7 in the range from 11 to below 15 (11,12,12,13,13,14,14)

1 in the range from 15 to below 18 (18).

Use the values as heights to draw the histogram.

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max2010maxim [7]
<h3>━━━━━━❃━━━━━━</h3>

<h3>Part one :</h3>

As it is given :

Present age of mom : Present age of son = 6 : 1

Therefore let :

  • Mother's age be 6x

  • Son's age be x

<h3>Part two :</h3>

Ages after 10 year :

  • Mom's age = 6x + 10

  • Son's age = x + 10

<h3>Part three :</h3>

The ages after 10 years are given in rational of 8 : 3.

Which means :

Mom's age after 10 years : Son's age after 10 years = 8 :3.

Now :

\scriptsize \purple{ \boxed{ \scriptsize \dfrac{ \text{Mom's age after 10 years}}{ \text{son's age after 10 years}}= \dfrac{8}{3} }} \star

\\  \\

So :

\small\sf \dashrightarrow \dfrac{6x + 10}{x + 10} =  \sf \dfrac{8}{3}

\\  \\

\small\sf \dashrightarrow \dfrac{3(6x + 10)}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small \sf \dashrightarrow \dfrac{18x +30}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small\sf \dashrightarrow \dfrac{18x +30}{1} =  \sf \dfrac{8(x + 10)}{1}

\\  \\

\small \sf \dashrightarrow 18x +30=  \sf 8(x + 10)

\\  \\

\small\sf \dashrightarrow 18x +30=  \sf 8x + 80

\\  \\

\small\sf \dashrightarrow 18x - 8x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x =  \sf 80 - 30

\\  \\

\small \sf \dashrightarrow 10x =  \sf 50

\\  \\

\small \sf \dashrightarrow  \dfrac{10x}{10}  =  \sf  \dfrac{50}{10}

\\  \\

\small \sf \dashrightarrow  \dfrac{1\cancel0x}{1\cancel0}  =  \sf  \dfrac{5\cancel0}{1\cancel0}

\\  \\

\small\bf \dashrightarrow x = \pink 5

\\

<h3>Part four :</h3>

We know :

\footnotesize \hookrightarrow \sf Son's \: age = x

\footnotesize \hookrightarrow \sf Son's \: age =  \red{5 \: years}

\\  \\

\footnotesize \hookrightarrow \sf Mother's \: age  = 6x

\footnotesize\hookrightarrow \sf Mother's \: age  = 6 \times 5

\footnotesize \hookrightarrow \sf Mother's \: age  =  \bf \red{30 \: years}

<h3>━━━━━━❃━━━━━━</h3>

And all we are done ! ㋛

<h3>~\pmb{\cal W\frak{indy}M\frak{int}}༄</h3>
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