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vagabundo [1.1K]
3 years ago
13

8x= 4x - 32 solve for x

Mathematics
2 answers:
stealth61 [152]3 years ago
7 0

Solve for x.

8x=4x-32

Subtract 4x from both sides.

4x=-32

Divide by 4 on both sides.

x=-8

answer: x=-8

Maru [420]3 years ago
3 0

Answer:

x=-8

Step-by-step explanation:

8x=4x-32

4x-8x=32

-4x=32

x=32/-4

x=-8

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I NEED HELP FAST!!! <br> 3x^3(4x^4+5x^2-2x-9+2x^2) <br><br><br> (Not multiple choice btw)
SIZIF [17.4K]

Answer:

12x^7+21x^5-33x^3

Step-by-step explanation:

12x^7+15x^5-6x^3-27x^3+6x^5

12x^7+21x^5-33x^3

6 0
3 years ago
If tan x° = 3 divided by y and cos x° = y divided by z ,what is the value of sin x°?
DedPeter [7]
Given:
tan x = 3/y
cos x = y/z

Because tan x = sin(x)/cos(x), therefore
sin x = tan(x)*cos(x)
         = (3/y)*(y/z)
         = 3/z

Answer: a) sin x = 3/z
8 0
3 years ago
A piece of copper wire which is 56cm long is bent to form a rectangle of area 171cm².find the length and the width of this recta
devlian [24]

Answer:

Length= 19cm

Width= 9cm

Step-by-step explanation:

let the length of the rectangle be L cm and its width be W cm.

Perimeter of rectangle= 56cm

2L +2W= 56

L +W= 56 ÷2

L +W= 28

L= 28 -W -----(1)

Area of rectangle= length ×width

LW= 171 -----(2)

Susbt. (1) into (2):

W(28 -W)= 171

28W -W²= 171 <em>(</em><em>expand</em><em>)</em>

W² -28W +171= 0 <em>(</em><em>bring</em><em> </em><em>everything</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em>)</em>

(W -19)(W-9)= 0 <em>(</em><em>factorise</em><em>)</em>

W-19=0 or W-9=0

W= 19 or W= 9

Subst into (1):

L=28 -19 or L= 28 -9

L=9 or L= 19

Since we usually take the longer side of the rectangle to be its length, L= 19 and hence W=9.

Therefore its length is 19cm and its width is 9cm.

3 0
3 years ago
Solve V = 1/3πr2h for h.
Rashid [163]

Step-by-step explanation:

v=1/3nr2h for h

3(v)=3(1/3nr2h)

3v/2nrh=2nrh/2nr

3v/2nrh=h

h = 3v/2nrh

7 0
3 years ago
Line segment AB was translated 2 units right and 7 units down to create line segment CD. A transversal intersects the two line s
belka [17]
These are correct statements:

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- </span>Since ∠1 and ∠3 are corresponding angles, they are congruent.
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- </span><span>Since ∠1 and ∠2 are corresponding angles, they are congruent. These are also not corresponding, they are supplementary.

- </span><span>Line segments AB and CD are perpendicular. They are not crossing over each other.</span>

- <span>Since ∠1 and ∠4 are alternate interior angles, they are congruent. They are not corresponding, they are supplementary. </span><span>∠1 and </span><span>∠3 are corresponding just like </span>∠2 and <span>∠4. </span>






6 0
3 years ago
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