Find an equation perpendicular to x=1 and passing through (8,-9)
1 answer:
Answer:
Step-by-step explanation:
We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).
Note that x=1 is a <em>vertical line </em>since x is 1 no matter what y is.
This means that if our new line is perpendicular to the old, then it must be a <em>horizontal line</em>.
So, since we have a horizontal line, then our equation must be our y-value of our point.
Our y-coordinate of our point (8,-9) is -9.
Therefore, our equation is:
And this is in standard form.
And we're done!
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Step-by-step explanation:
Answer:
Expression:
Value where y = 20
2
Step-by-step explanation:
Let's take a look at the sentence:
3 less than the quotient of y and 4
3 less indicates that you will subtract
- 3
Quotient means the result of division.
So if we combine the two, it says 3 less than the quotient so we subtract 3 from the quotient:
So if y = 20, we just substitute the y with 20