<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em><em>✌</em>
Here are some very good video that explain how. very short and easy too. http://virtualnerd.com/pre-algebra/linear-functions-graphing/rate-of-change-slope/finding-slope/slop... math antics on youtube is great for help too
Hello!
So, according to the problem, the heart rate of a bear during hibernation is 
its original amount.
So we can write an equation to help us understand this.
of sr = 28
We can use inverse to make this easier to solve. 2 × 28 = sr.
So, in simple form, we multiply.
28 × 2 = 56
Our final answer would be:
A bears heart rate during the summer would be 56 beats per minutes.
<em>waffletowne. </em>
Answer: Quadratic; 6x^2, x, -12
Detailed Explanation:
The highest power of the function (degree) is 2. Therefore it is a quadratic function. The quadratic term is 6x^2 since its power is 2, the linear term is x since its power is 1 and the constant term is -12.
Answer:
y = 1/4x - 8
Step-by-step explanation:
So we do not have the capabilities of graphing but I will help you find the equation.
Slope intercept form: y = mx + b
b = y intercept
m = slope
Put your equation together.
y = 1/4x - 8
