22a+15c=228
a+c=11
a=11-c
22(11-c) + 15c = 228
242-22c + 15c = 228
-7c=-14
C = 2 (two children)
Remember how a + c = 11
a + 2 = 11
A= 9
9 adults, 2 children.
Answer:
598 books
Step-by-step explanation:
Let x be the number of books in the 3rd pile. We will have then:
1st pile: 2x + 10
2nd pile: 2x
3rd pile: x
3000 = (2x + 10) + (2x) + (x)
3000 = 5x + 10
3000 - 10 = 5x
2990 = 5x
2990/5 = x
x = 598 books in the third pile!
We can check that:
3000 = 2*598 + 10 + 2*598 + 598
3000 = 1196 + 10 + 1196 + 598
3000 = 3000 CHECK!
8+12=20
20+12=32
Just keep adding by 12
From points (2, 0) and (6, 0), you can get base = 6 - 2 = 4.
From point (8, 5), you get a height of length 5.
A = bh/2 = 4 * 5/2 = 10
Area = 10 square units
Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
