R varies inversely with x . if r= -2 when x=6 what is the value of r when x= -3?

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

Answer:

r = 4

Step-by-step explanation:

Given that r varies inversely with x then the equation relating them is

r = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition r = - 2 when x = 6

k = rx = - 2 × 6 = - 12

r = $\frac{-12}{x}$ ← equation of variation

When x = - 3, then

r = $\frac{-12}{-3}$ = 4

You might be interested in

20c + 8d +10c - 5d<br><br><br> please answer you would get 15 points!

Rudik [331]

I think 30c+3d would be the correct answer.

4 0

3 years ago

Read 2 more answers

Describe the nature of the roots for this equation.<br> 3x^2+x-5= 0

m_a_m_a [10]

Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

$3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}$