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solong [7]
3 years ago
14

Solve. x-3y+2z=1 -x+4y-4z=1 5x-y+6z=9 Write answer in the form (x,y,z).

Mathematics
2 answers:
zhenek [66]3 years ago
8 0
  1x - 3y + 2z = 1 →  1x - 3y + 2z = 1
 -1x + 4y - 4z = 1 → -1x + 4y - 4z = 1
 5x - 1y + 6z = 9 →           y - 2z = 2

  1x - 3y + 2z = 1 
 -1x + 4y - 4z = 1 → -1x + 4y - 4z =  1 → -5x + 20y - 20z = 5
 5x - 1y + 6z = 9 → 5x - 2y + 6z = 9 →  5x -     1y +   6z = 9
                                                                           19y - 14z = 14

    y -  2z =  2 → 19y - 38z = 38
19y - 14z = 14 → 19y -  14z = 14
                                   -24z = 24
                                    -24    -24
                                         z = -1
   y - 2z = 2
y - 2(-1) = 2
    y + 2 = 2
        - 2 - 2
          y = 0

     x - 3y + 2z = 1
x - 3(0) + 2(-1) = 1
         x - 0 - 2 = 1
               x - 2 = 1
                 + 2 + 2
                    x = 3

(x, y, z) = (3, 0, -1)
hodyreva [135]3 years ago
4 0
I hope this helps you

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