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mars1129 [50]
2 years ago
11

A circle has a radius of 6 yards. A sector of the circle that is 12. 56 yards² is painted. What is the angle measurement of the

painted sector?
A. 9 degrees

B. 11 degrees

C. 40 degrees

D. 45 degrees
Mathematics
1 answer:
Fittoniya [83]2 years ago
5 0

Answer:

your answer is D.45 degrees

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4/10-3/10<br><br><br> how do i do this please hurryyyy
oee [108]

Answer:

its 1/10

Step-by-step explanation:

4/10-3/10=1/10

7 0
3 years ago
Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t
Anika [276]

Answer:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

Step-by-step explanation:

Given

\int\limits {\frac{x}{x^4 + 16}} \, dx

Required

Solve

Let

u = \frac{x^2}{4}

Differentiate

du = 2 * \frac{x^{2-1}}{4}\ dx

du = 2 * \frac{x}{4}\ dx

du = \frac{x}{2}\ dx

Make dx the subject

dx = \frac{2}{x}\ du

The given integral becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

Recall that: u = \frac{x^2}{4}

Make x^2 the subject

x^2= 4u

Square both sides

x^4= (4u)^2

x^4= 16u^2

Substitute 16u^2 for x^4 in \int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du

Simplify

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

In standard integration

\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)

So, the expression becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)

Recall that: u = \frac{x^2}{4}

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

4 0
3 years ago
What numbers are 0.6 unit from 1.3 on a number line?
ruslelena [56]

Answer:

A

Step-by-step explanation:

HOEP IT HELPS I TRY MY BEST

6 0
3 years ago
Please help right now!!!!! Solve the system of equations below. x + y = 7 2x + 3y = 16
motikmotik

Answer:

x=5 and y=2.

Step-by-step explanation:

We have been given a system of equations. We are asked to solve our given system.

x+y=7...(1)

2x+3y=16...(2)

From equation (1), we will get:

x=7-y

Upon substituting this value in equation (2), we will get:

2(7-y)+3y=16

14-2y+3y=16

14+y=16

14-14+y=16-14

y=2

Now, we will substitute y=2 in equation (1).

x+2=7

x+2-2=7-2

x=5

Therefore, the point (5,2) is solution for our given equation.

7 0
3 years ago
PLEASE ANSWER ASAP I WILL MARK BRAINLY
AURORKA [14]

Answer:

first and third

Step-by-step explanation:

Emma used the product instead of the quotient and forgot the parentheses in x-4.5

8 0
3 years ago
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