Answer:
Type I error occurs when the null hypothesis, H0, is rejected, although it is true.
Here the null hypothesis, H0 is:
H0: Setting weekly scheduled online interactions will boost the well being of people who are living on their own during the stay at home order.
a) A Type I error would be committed if the researchers conclude that setting weekly scheduled online interactions will not boost the well being of people who are living on their own during the stay at home order, but in reality it will
b) Two factors affecting type I error:
1) When the sample size, n, is too large it increases the chances of a type I error. Thus, a sample size should be small to decrease type I error.
2)A smaller level of significance should be used to decrease type I error. When a larger level of significance is used it increases type I error.
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Jill had a total score of 40 on 13 quizzes, so her average was
40/13 ≈ 3.08
_____
1 quiz @ 1 = total of 1
3 quizzes @ 2 = total of 6
4 quizzes @ 3 = total of 12
4 quizzes @ 4 = total of 16
1 quiz @ 5 = total of 5
total score = 1 + 6 + 12 + 16 + 5 = 40
total quizzes = 1 + 3 + 4 + 4 + 1 = 13
Answers:
- AE = 26
- AN = 58
- CT = 22.5
- Perimeter of triangle AEN = 127
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Work Shown:
Because points C, P, and T are midpoints of the sides of triangle AEN, this means the segments CP, PT, and CT are midsegments of triangle AEN.
The segment PT = 13 is a midsegment of the larger triangle, and it is parallel to the side AE. Recall the midsegment is half as long as its parallel side.
This means,
PT = (1/2)*AE
2*PT = AE
AE = 2*PT
AE = 2*13
AE = 26
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We'll use the same idea to find AN
CP = (1/2)*AN
2*CP = AN
AN = 2*CP
AN = 2*29
AN = 58
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And we can also say,
CT = (1/2)*EN
CT = (1/2)*43
CT = 22.5
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Add up the sides of triangle AEN to find its perimeter
Perimeter of triangle AEN = (AE)+(EN)+(AN)
Perimeter of triangle AEN = (26)+(43)+(58)
Perimeter of triangle AEN = 127
