Solve for x. Assume that lines which appear tangent are tangent.
1 answer:
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Long leg = 8 → opposite
short leg = 6 → adjacent
hypotenuse = ?
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80
tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33
short leg = 6 → adjacent
hypotenuse = ?
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80
tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33