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3 years ago

Solve for x. Assume that lines which appear tangent are tangent.

Mathematics

1 answer:

Lunna [17]3 years ago

4 0

Presumably, x is standing in for the question mark.

The pair of vertical angles (DFE and CFV) shown here both have measure 125°. This angle measure is equal to the average of the measures of the arcs intercepted by the chords CE and DV.

So we have

angle DFE = 1/2 (arc CV + arc DE)

125° = 1/2 (x + 200°)

250° = x + 200°

x = 50°

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The Varners live on a corner lot. Often children cut across their lot to scar walking distance. The diagram to the right represe

icang [17]

About 12.56 units.
Solve for x by plugging in values into Pythagorean theorem.
$a^{2} +b^{2} = c^{2}$
$x^{2} +(x+12)^{2} = 34^{2}$
Simplify
$2x^{2} + 24x+144 = 1156$
Subtract 144 from both sides
$2x^{2} + 24x = 1012$
divide both sides by 2
$x^{2} + 12x = 506$
complete the square
$x^{2} + 12x + 36 = 506 +36 . = (x+6)^2 = 542$
take the square root of both sides.
$x+6 = 23.28$
subtract by 6 to get about 17.28 for x.
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3 years ago

What are the values of x and y?

Ede4ka [16]

Step-by-step explanation:

In figure:

∠PRT+∠RTP+∠TPR=180

(angle sum property of triangle)

⇒x+(180

−∠RTQ)+60

=180

(linear pair)

⇒x+(180

−97

)+60

=180

⇒x=31

Now, ∠PRT+∠TRQ+∠QRS=180

(angle of straight line)

⇒x+48

+y=180

⇒31

+48

+y=180

⇒y=101

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FromTheMoon [43]

Answer:

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Step-by-step explanation:

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