How to solve this problem (4x+3y)2=
2 answers:
You need to distribute the 2 so it equals 8x+6y
(4x + 3y)² = (4x + 3y)(4x + 3y)
(4x + 3y)(4x + 3y) = 4x(4x + 3y) + 3y(4x + 3y)
4x*4x + 4x*3y + 3y*4x + 3y*3y
16x² + 12xy + 12xy + 9y²
16x² + 24xy + 9y²
Therefore (4x + 3y)² = 16x² + 24xy + 9y²
I hope this helps.
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