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3 years ago

Evaluate 10m + n2/4 when m = 5 and n =4

Mathematics

2 answers:

AnnZ [28]3 years ago

8 0

I think the answer is 52

Misha Larkins [42]3 years ago

3 0

Answer:

Step-by-step explanation:

10(5) + (4)2/4

50 + 8/4

50 + 2

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PLEASE HELP! WILL GIVE BRAINLIEST AND EXTRA POINTS

Varvara68 [4.7K]

Answer:

1,3,4

Step-by-step explanation:

5 0

3 years ago

Solve the system below using elimination {5x+9y= -10} {7x+10y= -1}

bixtya [17]

∑Hey , jillianwagler ⊃

Answer:

x = 7, y = -5

Step-by-step explanation:

Given~:

Solve the system below using elimination

{5x+9y= -10}

{7x+10y= -1}

Solve:

$\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}$

Isolate x ( 5x + 9y = -10 ) : $\mathrm{x=\frac{-10-9y}{5}}$

Substitute: $\mathrm{x=\frac{-10-9y}{5}}$

$\begin{bmatrix}7\cdot \frac{-10-9y}{5}+10y=-1\end{bmatrix}$

$\begin{bmatrix}\frac{-70-13y}{5}=-1\end{bmatrix}$

Isolate y : $\frac{-70-13y}{5}=1:y=-5$

Substitute: $y=-5$

$x=\frac{-10-9\left(-5\right)}{5}=7$

Hence, $x=7$

Therefore, the solution for $\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}$ are:

$x=7,\:y=-5$

xcookiex12

8/19/2022

6 0

2 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

I’m about to take the test please hurry! I will give brianliest.

scZoUnD [109]

Answer:

i think its 358

Step-by-step explanation:

5 0

3 years ago

a local business was looking to hire a landscaper to work on their property. they narrowed their choices to two companies. flour

ANTONII [103]

Flourish- 120x
Green Thumb- (70x)=1600

Flourish- 120*35= $4200
Green Thumb- (70*35)+1600= $4050

It would be less expensive to hire Green Thumb Landscapers. There is a $150 difference between the two

It would take 32 hours of work for the cost to be the same for both companies

7 0

3 years ago