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Gekata [30.6K]
3 years ago
15

Part 1

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Part 1

The n th term of a geometric sequence is

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Given a_{6} = 128, then

a(2)^{5} = 128, that is

32a = 128 ( divide both sides by 32 )

a = 4 ← first term

Part 2

a_{21} = 4(2)^{20} = 4 × 1048576 = 4194304

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