Question

Part 1

Answer 1

Answer:

see explanation

Step-by-step explanation:

Part 1

The n th term of a geometric sequence is

$a_{n}$ = a$(r)^{n-1}$

where a is the first term and r the common ratio

Given $a_{6}$ = 128, then

a$(2)^{5}$ = 128, that is

32a = 128 ( divide both sides by 32 )

a = 4 ← first term

Part 2

$a_{21}$ = 4$(2)^{20}$ = 4 × 1048576 = 4194304