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kipiarov [429]
3 years ago
8

Solve by quadratic formula. x squared plus x plus 1 = 0

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

Remember that the quadratic formula is: \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}.


a stands for the coefficient of the first term, the one associated with the x^2, b stands for the coefficient of the second term, the one associated with x, and c stands for the value of the constant.


In x^2 + x + 1 = 0, our a-value is 1, our b-value is also 1, and our c-value is also 1.


Thus, when we plug in our values into our formula, we get the answer:

\dfrac{-1 \pm \sqrt{1^2 - 4(1)(1)}}{2(1)} = \dfrac{-1 \pm \sqrt{-3}}{2}


Simplifying this answer using i = \sqrt{-1}, we get our final answer of:

\boxed{x = \dfrac{-1 \pm i\sqrt{3}}{2}}

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Answer:

y=8x-67

Step-by-step explanation:

So the question is what is the equation for the following two coordinate points?

Well to start off what is the formula? The formula is called the linear equation. Which is y=mx+b. What does these letters or "variables" mean or represent?! Welp, m stands for the slope, which is "Δy over Δx." Some people call say "the change of y over x." I call it the rise over run. So it is saying y over x. The b in the linear equation is the y-intercept. The y-intercept is when the line crosses the y-axis.

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