It looks as though there are 25 21-40 year-olds. 40% of 25 is 10, this is the amount that are AGAINST the increase. Therefore the ones in favor for the increase must be 25 - 10 = 15.
You should be able to follow the same process to get the 41-60 year-olds against an increase. Just be sure to read the given information carefully
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.
Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:
The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.
Thus, the lowest score of test A is given by 40(21) + 50 = 890
Therefore, the lowest score of test A is 890.
Part B:
The mean score is a measure of location, so both
addition and multiplying the mean score of test B by 40 and adding 50
to the result will affect the lowest score of test A.
Thus, the mean score of test A is given by 40(29) + 50 = 1,210
Therefore, the mean score of test A is 890.
Part C:
The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50
to the result will not affect the standard deviation of test A.
Thus, the standard deviation of test A is given by 40(2) = 80
Therefore, the standard deviation of test A is 80.
Part D
The Q3 score is a measure of location, so both
addition and multiplying the Q3 score of test B by 40 and adding 50
to the result will affect the Q3 score of test A.
Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170
Therefore, the Q3 score of test a is 1,170.
Part E:
The median score is a measure of location, so both
addition and multiplying the median score of test B by 40 and adding 50
to the result will affect the median score of test A.
Thus, the median score of test A is given by 40(26) + 50 = 1,090
Therefore, the median score of test A is 1,090.
Part F:
The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50
to the result will not affect the IQR of test A.
Thus, the IQR of test A is given by 40(6) = 240
Therefore, the IQR of test A is 240.
Answer:
Step-by-step explanation:
The answer is geosphere and hydrosphere
Answer:
The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
Step-by-step explanation:
The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.
A quality control inspector samples 2 computer chips.
The number of ways to select at least 1 defective chip is:
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
The number of ways to select 1 defective chip is: 
ways.
The number of ways to select 2 defective chips is:
ways.
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
= 30 + 3
= 33
Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
